A 50 pF parallel-plate capacitor with an air gap between the plates is connected to a...

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A 50 pF parallel-plate capacitor with an air gap between the plates is connected to a 50V battery. A Teflon (K=2) slab is the

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Answer 1

Answer #1

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Connected voltage = 50 V

Initial Capacitance = 50 pF

Capacitance aftyer filling the gap = 2 x 50 = 100 p F

It is clearly stated that, battery is disconnected only after the insertion of teflon slab

When disconnected, as no other parameters are changing, the potential difference will remain the same .

So PD = 50 V

Correct option is 50 V

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Answer 2

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