Question

3. Here we use 4.184 for our calorimetry constant, since that is how much energy it takes to raise 1 gram of water by 1 degree Celsius. But what if we did not know that? How could I calibrate our calorimeter to find this value? -10 points 4. What are 2 sources of error for this experiment (you cannot simply say human error)? how would the error effect the measurement? - 10 points 5. How much energy would be transferred if 20 grams of ice were added to the calorimeter? (Hint you will need the equation Q = mc) - 10 points 6. Why is there no temperature component to the equation for finding the energy required for a materials phase change? - 10 points 7. The specific heat of ethanol is 2.46 -- what would have been the final temperature for each metal if 50 mL of ethanol were used instead of 50 mL of water? - 12 points

Answer 1

can 5) fax determining the calorisister coustaut we the formula , c = Q AT for determining the Q, we the formula Q - IXV XT Where, I > Currow T Tinne un Voltage We can determine this experimentally by paking current through the calorioneter for a set of time. The errors will be asiae deie to fluctuating usilue of current and voltage. This error will alter the desired have to take several measurements to observe the most faucurable outcome. value Do, iwe 5 ) man = 209 C = 4.184 I colo : Q=mca 20g x 4.184 Ilg 83.68 J E) It is because we have already calculated the Cralus from the above experimentally by using, & CaQAT CS Scanned with CamScanner