Question

For a normal​ distribution, verify that the probability​ (rounded to two decimal​ places) within

a) 2.23 standard deviations of the mean equals ________

b) Find the probability that falls within 1.35 standard deviations of the mean.

Answer 1

A)

P( -2.23 <Z <2.23 ) = 0.97

B) P( -1.35 <Z < 1.35) = 0.82

Solution file is attached go through it

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/ Hence PlM-1.350 LX <Mt 1.350) = 0.82 for a nomal Disth verify that the prob. (two decimal within 2.23 standard deviation of Mean. that is find P(-223 2222-23) P(-2:23 <2<223)=0-97 = P(4-2230<x5472230) =0.97 - 2.23 (M)=0 223 Mean 76-2:23 < Z <223)= 0.97425 €0.97 ( Ramel tema Decimal) A prob. find with help of Standard Nunal Digith. find prob. that falls within 1:35 standard Derlastin. P (M-1:350 <7 <4+1:355) = P(-1+3542<1:35) = 0.82 Mio 1.35 Po (M=1.350<x< 4+ 1.350)=P(+1:35 <Z21:35) P(-1.35 < 221:35) = 0.82298 ~ 0.82 ( upto two Decimal) -1.35

Thanks