Question

1. What is the fpr in mm/rev when the spindle speed is 6000 rpm and the feed rate is 0.88 m/min? 2.Why engineers should learn
0 0
Add a comment Improve this question Transcribed image text
Answer #1

Page-1 soll. given, spindle speed (N)= 6000rpm feed rate (I) 0.88 m/min 880mm/min feed per revolution (for) = ? fpr= I 880 mm

Add a comment
Know the answer?
Add Answer to:
1. What is the fpr in mm/rev when the spindle speed is 6000 rpm and the...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • A grinding operation takes place with a 295 mm wheel with a spindle speed of 4730 RPM. The workpi...

    A grinding operation takes place with a 295 mm wheel with a spindle speed of 4730 RPM. The workpiece feed rate is 248 mm/min and the depth of cut is 0.0025 mm. Given that C-3.5 grains/mm2 and r-12, calculate: -The length of the metal chips 3 Decimals, Unit mm Answer 0.859 The Grinding surface speed (V) Unit: mm/sec Answer73089.76 calculate -The thickness of the metal chips Unit: mm (6 decimals required) Answer: 8.333333 The volume of the chips Answer format:...

  • a) A workpiece (φ-75 mm, 1 275 mm) is machined using turning at a feed rate of 0.25 mm/rev. At a cutting speed- 3.5 m/s, the turning tool is ineffective after machining 3 parts, and at a cutting s...

    a) A workpiece (φ-75 mm, 1 275 mm) is machined using turning at a feed rate of 0.25 mm/rev. At a cutting speed- 3.5 m/s, the turning tool is ineffective after machining 3 parts, and at a cutting speed = 2.5 m/s, the turning tool is effective for producing 20 parts. Calculate the Cutting Speed that will allow 30 parts to be machined between tool changes [20 marks] b) An aluminium alloy workpiece (tensile strength - 325 N/mm2 and yield...

  • REVISIONS DESCRIPTION ZONE REV DATE APPROVED 4 X 0.375 THRU 2.250 1.062 1.750 B ,0.437 0.562...

    REVISIONS DESCRIPTION ZONE REV DATE APPROVED 4 X 0.375 THRU 2.250 1.062 1.750 B ,0.437 0.562 0.500 0.750 1.375 2.500 - 3.000 - 4.000 NOTES: 1. UNLESS OTHERWISE SPECIFIED, ALL DIMENSIONS ARE IN INCHES. 2. MATERIAL: STEEL 350 BHN TOLERANCES DECIMALS ANOLES GEORGIA SOUTHERN XX 1 X.X +0.1 UNIVERSITY X.Xox - 0.01 X.XX - 0.01 X.XOOX 0.001 DESCRIPTION X.XXX - 0.0001 THIRD ANGLE PROMOTION A SZE PARENT ASSEMBLY OWO NO. SEE NOTE 2 LA PLATE DESIGNED BY SCALE 1.1 RELEASE...

  • 02: A bar of 60 mm diameter and length of 3 meter is used to produce 500 pieces on a center lathe having the follow...

    02: A bar of 60 mm diameter and length of 3 meter is used to produce 500 pieces on a center lathe having the following characteristics: . Maximum rotational speed .Minimum rotational speed .Number of speeds Lathe overall efficiency The turning process is performed at 40 m/min cutting velocity. 0.5 mm/rev longitudinal feed, 0.25 mm/rev transverse feed and 2 mm depth of cut REQUIRED 1. Calculate the TWELVE rotational speeds in rpm. 2. What rotational speed would you choose? 3....

  • During the turning operation, the cutting speed = 2.95 m/s, the feed f = 0.40 mm/rev,...

    During the turning operation, the cutting speed = 2.95 m/s, the feed f = 0.40 mm/rev, the depth of cut, d = 1.83 mm, the rake angle α = 5° and the deformed chip thickness= 0.58 mm. The workpiece material has volumetric specific heat = 2.96 x10-3 J/mm3- °C, thermal diffusivity = 0.783 cm2/s and specific energy = 1.036 J/mm3, obtained at feed equal to 0.25 mm/rev. The correction factor for the specific energy is CF = 0.75 to-0.21, when...

  • Fundamentals of Mechanical Manufacturing Technology: Exercise5 Material-removal Rate The rate (MRR) in turning is the volume...

    Fundamentals of Mechanical Manufacturing Technology: Exercise5 Material-removal Rate The rate (MRR) in turning is the volume of material removed per unit time, with the units of m/min De + D t also can be written as MRR = drv Do: Orignal diameter of workpiece,mm Dr: Final diameter of workpiece, mm Davg: Average diameter of workpiece, mm d: Depth of cut, mm f: Feed, mm/rev 4feed rate ofdf-㈢ )-mm, the distance traveled is l mn, the cutting time is Eq. (2)...

  • In a turning operation, cutting speed = 1.8 m/s, feed = 0.30 mm/rev, and depth of...

    In a turning operation, cutting speed = 1.8 m/s, feed = 0.30 mm/rev, and depth of cut = 2.6 mm. Rake angle = 8°. After the cut, the deformed chip thickness = 0.56 mm and before the cut, the chip thickness = 0.26 mm. Determine (a) shear plane angle, (b) shear strain, and (c) material removal rate. Use the orthogonal cutting model as an approximation of turning

  • QUESTIONS LO MARKS 3.1 A cylindrical workpiece is turned on a lathe. The spindle speed of...

    QUESTIONS LO MARKS 3.1 A cylindrical workpiece is turned on a lathe. The spindle speed of the lathe is 2750 RPM and the feed is 0.01 cm The length of the part is 315 mm, the initial radius of the part is 60 mm, and a single cut is taken with a depth of 3 mm (a) How long (in seconds) will the turning operation take. Show all your working (1 marks) DM = b = 3.15 -= o.ll =...

  • • 23.44 Calculate the same quantities as in Example 23.1 for high-strength titanium alloy and at...

    • 23.44 Calculate the same quantities as in Example 23.1 for high-strength titanium alloy and at N=700 rpm. Use units from Ex 23.1, specify units of each term. (20%) Format Tools Table Window Help 28th ed Chapter 23 - Saved to my Mac Mailings Review View Shape Format ut References ABC Astboeddte AaBb Abd A 2 Example 23.1 Material-removal Rate and Cutting Force in Turning Given: A 150-mm-long, 10-mm-diameter, 304 stainless-steel rod is being reduced in diameter to 8 mm...

  • The flywheel of a steam engine runs with a constant angular speed of 475 rev/min. When...

    The flywheel of a steam engine runs with a constant angular speed of 475 rev/min. When steam is shut off, the friction of the bearings stops the wheel in 3.0 h. (a) What is the constant angular acceleration, in revolutions per minute-squared, of the wheel during the slowdown? rev/min2 (b) How many rotations does the wheel make before stopping? rotations (c) At the instant the flywheel is turning at 75 rev/min, what is the tangential component of the linear acceleration...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT