
When 4.5 V battery is connected to a resistor, the ammeter measures a current of 15...
An ammeter is connected in series to a battery of voltage
Vb and a resistor of unknown resistance Ru
(Figure 1) . The ammeter reads a current Io. Next, a
resistor of unknown resistance Rr is connected in series
to the ammeter, and the ammeter's reading drops to I1.
Finally, a second resistor, also of resistance Rr, is
connected in series as well. Now the ammeter reads
I2.
If I1/I0=4/5, find
I2/I0.
Express the ratio I2/I0 numerically.
I2/I0 =
A cylindrical resistor has diameter d, resistivity ρ, and length L. A battery with voltage V is connected to the resistor. Quantitatively explain (i.e. find the factor) how the resistance AND power dissipated would change given the following modifications. (Take each part on is own, not as a series of events!) (a) Doubling the length and tripling the cross section area of the resistor. (b) Replacing the resistor material with material that has 10 times higher resistivity. (c) Halving the...
Consider a circuit containing a 24 V battery and a 15 Ω resistor. We want to mesure the current in the circuit with an ammeter of internal resistance 3 mΩ and the voltage drop across the resistor with a voltmeter having an internal resistance of 100 kΩ. a. How should be the ammeter connected (series or parallel)? b. How should be the voltmeter connected (series or parallel)? c. Draw a schematic of the circuit d. Calculate the current across the...
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a 10 V battery connected to a resistor produces a 5 mA (milliamperes)current. what is the resistance?
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