The distance s that a certain object falls from a height of 450 ft in t...

Question

Question

math algebra

Answer 1

Answer #1

The distance s that a certain object falls is given by the formula

s=450-16t^2+(v*t)

We have to find the value of s when $t=3 \ and \ v=-2$

Substituting the value of 't' and 'v', we get

s=450-16(3)^2+((-2)*(3))

s=450-16(9)+(-6)

s=450-144-6

s=300ft

Hence the object will fall 300 feet, when $t=3 \ and \ v=-2$

Answer 2

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