HomeworkLib
Question

If an object is propelled upwards from a height of 128 feet at an initial velocity...

If an object is propelled upwards from a height of 128 feet at an initial velocity of 112 feet per second, then its height h (in feet) after t seconds is given by the equation

h(t) = -16t2 +112t +128

a) When does the object reach its maximum height? Determine answer analytically.

b) What is the object's maximum height?

science   Advanced-Physics   
0 0
Add a comment Improve this question Transcribed image text
Next > < Previous
Sort answers by oldest

Homework Answers

Answer #1

please upvote ? if you like my answer ?

0 0
Add a comment
Know the answer?
Add Answer to:
If an object is propelled upwards from a height of 128 feet at an initial velocity...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions

  • An object is propelled upward at an initial velocity of 32 feet per second at a....

    An object is propelled upward at an initial velocity of 32 feet per second at a. initial elevation of 48 feet above the ground. The free-fall model used to describe the motion is: s(t) = -16t2 + 326 +48 for Osts 3 (t seconds from release of object). Reference: Drop the Ball Activity The average velocity between t = 0 sec and t = 2 sec A) O feet per second B) 24 feet per second C) 12 feet per...

  • A projectile is launched straight up from ground level with an initial velocity of v0 per...

    A projectile is launched straight up from ground level with an initial velocity of v0 per sec. Neglecting air resistance, its height in feet, s, after t seconds after launch is given by the equation s = –16t2 + v0t. At what time(s) will the projectile reach a height of 112 feet when v0 = 96 feet/sec? After how many seconds will it return to the ground when v0 = 96 feet/sec?

  • An object is propelled upward at an initial velocity of 32 feet per second at an...

    An object is propelled upward at an initial velocity of 32 feet per second at an initial elevation of 48 feet above the ground. The free-fall model used to describe the motion is: s(t) = -1672 + 32t +48 for 03033 (t seconds from release of object). Reference: Drop the Ball Activity The average velocity between t = 2 sec and t = 3 sec A) -48 feet per second B) -24 feet per second C) 16 feet per second...

  • An object is thrown upward at a speed of 161 feet per second by a machine...

    An object is thrown upward at a speed of 161 feet per second by a machine from a height of 8 feet off the ground. The height h of the object after t seconds can be found using the equation h(t) = 16t2 + 161t + 8 When will the height be 67 feet? (Write both results, using a comma between). Round answers to the nearest hundredth. Select an answer Select an answer ict reach the ground? seconds 1 answer...

  • An object is thrown upward at a speed of 194 feet per second by a machine...

    An object is thrown upward at a speed of 194 feet per second by a machine from a height of 6 feet off the ground. The height hh of the object after tt seconds can be found using the equation h(t)=−16t2+194t+6h(t)=-16t2+194t+6 When will the height be 522 feet? (Write both results, using a comma between). Round answers to the nearest hundredth. When will the object reach the ground?

  • An object is thrown upward from a height of 6 feet at a velocity of 64...

    An object is thrown upward from a height of 6 feet at a velocity of 64 feet per second. The height of the object h is a function of time t. h(t) = -16+2 +64t + 6 At what time the function h will reach its maximum value.

  • an object propelled upwards with an acceleration of 2.0 m / s ^ 2 is launched...

    an object propelled upwards with an acceleration of 2.0 m / s ^ 2 is launched from rest. After 6 seconds the fuel runs out. Determine the speed at this time and the maximum height at which it reaches.

  • If a ball is thrown straight up into the air with an initial velocity of 95 ft/s, it height in feet after t second is given by y=95t–16t2

    If a ball is thrown straight up into the air with an initial velocity of 95 ft/s, it height in feet after t second is given by y=95t–16t2. Find the average velocity for the time period begining when t=1 and lasting(i) 01 seconds: (ii) 001 seconds:(iii) 0001 seconds:Finally based on the above results, guess what the instantaneous velocity of the ball is when t=1.

  • If an object is thrown with a velocity of v feet per second at an angle...

    If an object is thrown with a velocity of v feet per second at an angle of θ with the horizontal, then its flight can be modeled by, x = (v cos θ ) t and y = v (sin θ ) t - 16 t2 + h where t is in seconds and h is the object's initial height in feet above the ground. x is the horizontal position and y is the vertical position, and - 16 t2...

  • A model rocket is launched straight up from ground level with an initial velocity of 96...

    A model rocket is launched straight up from ground level with an initial velocity of 96 feet per second. Its height, in feet, after t seconds is given by the equation s(t)=-16t2+96t. At what time(s) will it reach a height of 80 feet? b. After how many seconds will it return to the ground? Question(s) a. and b. should also be answered in sentence form. In addition to showing the calculations that lead to your solution, write a synopsis of...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT