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In the circuit shown below, let Isi = 2 mA, I2 = 3 mA, RI = 2.5 k 2, R2 = 6 k2, R3 = 4 k. Use nodal analysis to find V and V2
Is = 2 mA , Vs - 6 V , R = 1.5 k 2 , R2 = 2 k - 2 , R3 = 6 k 2 , Re - 2.5 k 2 , Rs = 3 k12 . In the circuit shown below, let
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R2 Gka Ri © Isi R3 IS2 ( ↑ 12.5kr 4 κΩ 2 MA 37726 Tim Using nodal analysis at node (1) 2=0 I -2=0 2 Vi hat vi R2 R Using theQ : 1 4 From equation 17V-5V2=60 From equation 3 :- 2V2 - 2V +3V, -36=0 = 5V2 - 20,=36 Using & 15:- > 347, 1042 = 1.20 Z On aRi 1.5RR U2D С R2 R3 Vi 2KR bre VAGU Ru R5 3K22 1) Is 2mn 2.5682 nodal analysis is at ci- Using tu,-v2 VI 2=0 2.5 2 = > Qui t

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