Question

Below is an image from a double slit experiment obtained by shining a laser through one. I used a He-Ne Laser, wavelength = 6We will use the provided data to determine the experimental value of the wavelength of the laser used. To accomplish this, weL=10ft , 4,000 d- 0.50mm double ses o a 0 a O O o 0 الدی ) کے دا 3 le 1.00cm 1.30cm =


ive attached the results to the experiment help me how to find ym in oder to get the y values to plot the data and get the slope
0 0
Add a comment Improve this question Transcribed image text
Answer #1

Given. Id-dym ML şo > AmL d form=1 -9 Yo = 632.8x16X1X3.048 0.250X 163 Im = d=632.8x10 m d=0.250 X 103 m L= 10ft = 3.048m m Yfor the % enor you have to calculate Experimentel value of nexp. then apply formula the % Enarinda nexpo Ath -x 100. Ati Wohe

Add a comment
Know the answer?
Add Answer to:
ive attached the results to the experiment help me how to find ym in oder to...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • help solve for x and y Below is an image from a double slit experiment obtained...

    help solve for x and y Below is an image from a double slit experiment obtained by shining a laser through one. I used a He-Ne Laser, wavelength = 632.8 nm, and shined through two slits whose separation distance is d = 0.250 mm. The light was shined upon a sheet of paper taped to the wall and was 10.0 ft 4.00 inches away from the double slit. I circled the bright spots (constructive interference) and identified the central maximum...

  • Below is an image from a double slit experiment obtained by shining a laser through one....

    Below is an image from a double slit experiment obtained by shining a laser through one. I used a He-Ne Laser, wavelength = 632.8 nm, and shined through two slits whose separation distance is d = 0.250 mm. The light was shined upon a sheet of paper taped to the wall and was 10.0 ft 4.00 inches away from the double slit. I circled the bright spots (constructive interference) and identified the central maximum (m = 0). I saved the...

  • Please Help! can someone walk me through how O actually come up with slope? i inderstand...

    Please Help! can someone walk me through how O actually come up with slope? i inderstand that dym is the y values and ml is the x, but I cant figure out what those values are. I used a He-Ne Laser, wavelength = 632.8 nm, and shined through two slits whose separation distance is d = 0.250 mm. The light was shined upon a sheet of paper taped to the wall and was 10.0 ft 4.00 inches away from the...

  • Question 3: Calibrating the Double Slit You are attempting to perform a double slit experiment (see...

    Question 3: Calibrating the Double Slit You are attempting to perform a double slit experiment (see Figure 2): the distance between slits is 0.1 mm, the distance from the barrier to the screen is L = 2 m, and the distance from the coherent) laser light source to the barrier is t = 0.4 m. You are using red light, with a wavelength = 660 nm. You are worried that you have not perfectly centred the laser halfway between the...

  • 5. Fig. 9.2 shows the geometry of a double-slit interference experiment. If the light beam is...

    5. Fig. 9.2 shows the geometry of a double-slit interference experiment. If the light beam is a laser beam with a wavelength of 500 nm, the slit separation is d 0.3 mm, and the distance to the screen is L-0.7m, what is the value of x at the first minimum of the interference pattern (first minimum to the x side of the central maximum)? What is the value ofx at the first maximum of the interference pattern? What is the...

  • What causes the bright and dark fringes to appear on the screen in a double slit...

    What causes the bright and dark fringes to appear on the screen in a double slit interference experiment? m#2 m-1 m 2 mA screen igure 2. Description of a double slit interference pattern. Peaks represent bright spots. The constructive interference when the distances from the first slit to the screen and the second slit to the screen differ by a whole wavel ength than The two angles labeled theta can be considered equal when the distance to the screen, D,...

  • In a double-slit interference experiment the slit separation is 8.40 x 10-6 m and the slits...

    In a double-slit interference experiment the slit separation is 8.40 x 10-6 m and the slits are 2.80 m from the screen. Each slit has a width of 1.20 x 10-6 m. a) An interference pattern is formed when light with a wavelength of 450 nm is shined on the slits. How far (in meters) from the center of the interference pattern on the screen do the third order (m = 3) bright fringes occur? (1.5 pts) b) If a...

  • m-2 m= 1 m=2 mA screen Figure 2. Description of a double slit interference pattern. Peaks...

    m-2 m= 1 m=2 mA screen Figure 2. Description of a double slit interference pattern. Peaks represent bright spots. Th when the distances from the first slit to the screen and the second slit to the screen differ by a e constructive interference nd slit to the screen differ by a whole wavelength to the screen, D, is much greater than le. The two angles labeled theta can be considered equal when the distance whole wave multipl the slit separation....

  • Question 1 (1.5 points) This assignment is set up for sequential assessment. Complete each question and...

    Question 1 (1.5 points) This assignment is set up for sequential assessment. Complete each question and submit the answer before moving on to the next question. Correct answers for each question will be made available once the maximum number of attempts have been made for each submission. Double Slit Interference 1 Double Slit Interference Double Slit Screen Interference y=Ltane y 10 y = 0 L (destructive). L bright fringes: sine m=0, 11, 12,...(constructive) Dark fringes: above central: sin 8 =...

  • (1) Derive the equation that relates the wavelength λ to the distance Ym=1 of the m=1...

    (1) Derive the equation that relates the wavelength λ to the distance Ym=1 of the m=1 line. You must provide the justification for your derivation. (2) Describe, step by step, how the experimental data has to be analysed to determine the unknown wavelength λ3. You must be brief but clear in your description of the method. **You can just show me the working, I will provide explanations on my own** Aim Diffraction grating is used to determine the wavelengths of...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT