Question

Withdrew During Interval Adjusted Number at Risk During Interval 2 Cumulative Proportion Proportion Proportion who Died who Survived During Survived to End of Interval Interval Interval 44 ps Px+1 Interval х w 0 Alive at Died Start of During Interval Interval L. da 2456 543 1903 265 1616 243 1253 202 845 118 10 1 2 3 4 22 120 206 335

Please complete this clinical life table showing details (steps; calculation) for the first row.

please do fill out all chart!!

total 2456 patients

Thank you :)

Answer 1

The different components of a clinical life table are as follows:

$l_{x}$$\rightarrow$ number of alive at the start of interval; $d_{x}$ $\rightarrow$ number of deaths during the time interval; $w_{x}$ $\rightarrow$ withdrew during the interval; $l^{'}_{x}$ $\rightarrow$ adjusted number at risk during the interval and is given by, $l^{'}_{x}=l_{x}-\frac{w_{x}}{2}$ ;  $q^{'}_{x}$$\rightarrow$ proportion died during the interval and is given by, $q^{'}_{x}=\frac{d_{x}}{l^{'}_{x}}$ ;  $p^{'}_{x}$$\rightarrow$ proportion who survived during the interval and is given by,
P = 1 9 2
;  $P_{x+1}$$\rightarrow$ cumulative proportionsurvived to the end of interval and is given by, $P_{x+1}=p_{x}^{'}\times P_{x}$ ; but at the beginning, P(1)=0.

Interval (x)	Alive at the start of interval $l_{x}$	Died during interval $d_{x}$	Withdrew during interval $w_{x}$	Adjusted number at risk during interval $l^{'}_{x}$	Proportion who died during interval $q^{'}_{x}$	Proportion who survived during interval $p^{'}_{x}$	Cumulative proportionsurvived to the end of interval $P_{x+1}$
0	2456	543	10	$2456-\frac{10}{2}=2451$	$\frac{543}{2451}=0.222$	$1-0.222=0.778$	000'T
1	1903	265	22	$1903-\frac{22}{2}=1892$	$\frac{265}{1892}=0.140$	$1-0.140=0.860$	$0.778\times 1=0.778$
2	1616	243	120	$1616-\frac{120}{2}=1556$	$\frac{243}{1556}=0.156$	$1-0.156=0.844$	$0.860\times 0.778=0.669$
3	1253	202	206	$1253-\frac{206}{2}=1150$	$\frac{202}{1150}=0.176$	$1-0.176=0.824$	$0.844\times 0.669=0.565$
4	845	118	335	$845-\frac{335}{2}=677.5$	$\frac{118}{677.5}=0.174$	$1-0.174=0.826$	$0.824\times 0.565=0.466$