Question

A positively charged rod of length L = 0.220 m with linear charge density = 2.71 mc/m lies along the x axis as in the figure. Find the electric field at the position Pa distance 0.335 m away from the origin (Express your answer in vector form.) N/C р Submit Answer

Answer 1

given

length L = 0.22 m

charge density = $\lambda$ = 2.71*10^-3 C/m

x = 0.335 m

from the relation

electric field at point p is

E = $k\lambda L/(x^2-xL)$

E = 9*10^9*2.71*10^-3*0.22/(0.335^2-0.335*0.22)

E = 5.3658*10^6/(0.112-0.0737)

E = 1.4*10^8 i N/C