Question

Two workers pull horizontally on a heavy box, but one pulls twice as hard as the other. The larger pull is directed at 25.0° west of north, and the resultant of these two pulls is 410.0 N directly northward. Use vector components to find the magnitude of each of these pulls. Assume that the smaller pull has a component directed to the north. Enter your answers numerically separated by a comma.

Answer 1

Let the larges pull have inagnited Fi directed 6250 west of with. Let the smaller pull have maquitace F2 The resultant of Fi and Fa cerects along A with have magailude T-210N: F = Fitta can say the fa so that From the sepretry of the problem must to be directed along Nos some angle (0) of with of want eart west of with not force directe along north. Nowe let us consider Ē Co vrelinete axes at o on the direction besicher di F and &a enda Here the objects mover along F (hors). So not force along F rend, - Freda=0 Reaso, es agram. 0 Х are & zero. - 1 ve sign, or they are oppositely directed [

on on tere Fi andi - Farinda suda= ( F ) given that berper pull F.) have magnitude twice than the smaller full. - Fi=2 F2 Puthing 6 en , we have, 2F2 sada = zur & sex (250) on = a per 2 neu 25 - 57.6970 82 57.700 So, F2 derecto along 57-7° cont of woth. Now, net force along y axes, cur. F = F, cond, tfg conde [Fron dhagran) 2F2 condait F₂ Conde = F [F, = 22a] F2 [2 en 8, + conte] d. 2cond, conda 2llo 2x com (25") + con ( 57 7") F₂ = 174.69N

So, the smaller pull have magnitude a Fa= 174.69 N, (derected along 57.78 cast of north) On And the larger pull have magnitudo Fi = 2 F₂ = (2x 1746 g/n - 349.38 N (directed along 25° west of worth) (AM)
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