Quantum. In an experiment, a photon's frequency is measured to be 4 x 1016 Hz. What is the energy of the photon, in units of electron-Volts?
Givein in the question,
Frequency of the photon, n = 4 × 1016 Hz
Now, energy of a photon havin frequency n Hz is,
E = h × n
Hare, h= planck's constant
= 6.626 × 10-34 J.s
Thus energy in electron volt,
E = (h×n)/e = ( 6.626 × 10-34 × 4 × 1016)/ (1.6 × 10-19 ) = 165.65 electronvolt.
Answer, E = 165.65 eV.
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