Question

4 Timer Feedback A satellite has two bright lights at the end of its two solar panels to indicate its position. The distance between the two lights is 5.43 m. The wavelength of the light emitted by the Indicator lights is 565 nm. If a telescope with an aperture of 45.5 cm can just resolve the two Indicator lights, then how far is the satellite from the telescope? (Hint: Use the Rayleigh Criterion, and the small angle approximation sin() =tan(O).) 1 Tries 0/12 Send Feedback

Answer 1

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aperture of telescope = 45.5cm =D az 565om Just resolved o Ś y = 5.43m x=? minimum angular seperation of two points ewhich can be just resolved by an optical instriement 1-22 D where 5.43m ton = 2 = ? S. 43 9 - 1-22 X 565 X10 565x109 45.5x102 22 distance of the satellite from the telescope 2 5.43 X us.5x10 1.22x565x10 9 7 583x10th on 3583 km