Question

CALCULATE THE SUPPORT REACTION , DRAW FREE BODY DIAGRAM FOR EACH JOINT AND STATE YOUR RESUALT

ExamPLE 1 B 3KN zm 45° A n 2m

Answer 1

Example B 3 KN 0 um 2 Taking moment about a *), IMA Cy x 2 – 3X2 = 0 #cy = 3 KN (1) A 459 2m Ay +7, IVEO, cy Aytey = 0 & Ay = - Char3 KN = 3 kN (1). [H=0 Az = 3 kN (K).

Now consider Joint of FAB *, IF, = 0 AC * FAC = 3 KN (Tension). 3 KN FAL +1, 1 fiy = 0, 3 KN FAB-3=0 + 6 = S KN (Tension) consider joint a GB ↑ Fegsin 45' 45 3 KN Fee Cos45 ep Sin 45'+ 3 =0 Fee = -3/å KN = 312 kN (compression). 3 KN -fce cos45'- 3 = 0 FCBE - 3/2 KN = 312 kN (compression)