Question

D Question 9 1 pts A two-step mechanism has been proposed for the reaction between NO, and fluorine. Which piece(s) of data would lead a student to accept this mechanism? Select all that are correct. Step 1: NO, +F2 NO,F+F (slow) Step 2: F+ NONOF (fast) Overall: 2NO3 + F2-2NO3F The rate increases with the use of a platinum catalyst. The rate doubles when [53] is doubled and [NO] is held constant. The rate doubles when (NO) is doubled and [Fa] is held constant. The rate quadruples when [NO] is doubled and [F] is held constant. The rate quadruples when [F] is doubled and [NO] is held constant The rate quadruples when [F] and [NO] are both doubled.

Answer 1

ANSWER-

Correct statements are;

1) The rate increases with the use of platinum catalyst.

2) The rate doubles when [F2] is doubled and [NO2] is held constant.

3) The rate doubles when [NO2] is doubled and [F2] is held constant.

6) The rate quadruples when [F2] and [NO2] are both doubled.

Giveni 2-steps A reaction mechanism, step-1 NO + F₂ NO₂ftf (slow) Step 2 (fast) F + NO₂ NO₂f Overall : 2 NO2th 2 NO₂F Note: Slow step is the rate determing step. Expression for rate law can be given as; Ra K[NO2] [f2 The presence of a catalst increase the rate of a reaction lowering it's activation energy. Therefore, is the rate increases with the use of a Platinium catalyst. on doubling [2] Keeping [Nou] constant. Then, rate law; K [NO2] [2 f2] -) R = 2K [NO₂] [f₂] R' CS Scanned with CamScanner

-> R?=2 R On doubling y un The rate doubles when [52] is coobled and [NO2] is held constant [NO2 and keeping [f₂] constant Rate law; K [2 NO2] [ f₂ R's 2 K [ NO2] [f2] R = V i The rate doubles when [NO2] is doubled and [fa] is held constant. R = -> = 2R X] in The rate quadruples when [NO2] is doubled and [f₂] is held constant. This is wrong because rate doubles on doubling (NO2]. LX (1) The rate quadruples when [fa] is doubled and (NO2] is held constant. This is wrong, becaw pe rate doubles on doubling [f2]. CS Scanned with CamScanner

On doubling both [fa] and [NO₂]. Rate law R = = K [2 NO2] [2f2 R² = 2x2 K [Na] [f2] R?= 4 K [ NOZ If2] R² = 4 R y vi the rate quadruples when [[2] and [No2] are both doubled. -) =) CS Scanned with CamScanner