Question

Suppose liquid is stored fully in a spherical tank with radius R (3.25 m) and the outlet valve is opened at a constant flow rate of F (7.63 m3/min). The governing equation of the process is given as Te Rh? – žrth = $1R3 – Ft Determine the liquid level in the tank, h, after 14 min using modified Newton-Raphson with finite difference formula. Show at least 3 iteration of calculation.

Answer 1

Chemical Engineering (1) Given that Radius (Rt 3.25m Flow Rate (F) = 7.63 m3/min .RO 23.25m h EF=7.63 goverming equation is ARh? - 17h3 = 4nR3 Ft at Intial Condition to height of liquid Ch) = 6.50m We need to find, the h when a = 14 min By Using Modified Newton Raphson Method how = had t ex f ( trew' hew) here finite difference is de 14-0= 4.66 min 3 So, (1 h = 6.50 + l . f (it, , h) h = 6.50+ 4.66 . f (4.66, hi ) his 4.89 m CH) ha = 4.89 + 4.66 of (9.32 ha) h₂ - 3- 284 m Cul) h3 = 3-284+4.66 f (14 43) Tha = 1.67m. so, The liquid Leight after 14 min will be 1.67m.