Question

12p

EXCEPTIONS: It's easier to ask forgiveness than permission. Try the code and catch the errors. The other paradigm is 'Look before you leap' which means test conditions to avoid errors. This can cause race conditions. 1.Write the output of the code here: class MyError(Exception): pass def notZero(num): if num == 0: raise MyError def run(f): try: exec(f) except TypeError: print("Wrong type, Programmer error") except ValueError: print("We value only integers.") except Zero Division Error: print("You can't divide by 0") except NameError: print("Check your spelling!!") except MyError: print("O's are not allowed on test") testcode=['print(int("four"))', 'notZero(0)', 'print(1/0)','x = 1 + "hello",'spellingWord="Banana"\nprint(spollingWord)' for test in testcode: run(test) 2. In the Gas Mileage assignment, we needed to check input to make sure it was a float. One way to accomplish this is with python exception handling: try, raise, except. The function getUserFloat receives one parameter, a string that contains a prompt for input. It must return a float that contains the number input by the user. If the user enters a non- number or a number less than or equal to zero it should prompt them again. Sample Algorithm def getUserFloat(prompt): Loop until you get a correct value try: get input try to make it a float #if it doesn't, it will call except check to be sure number is in valid range give error message if not in range return value if it is except Error: #which kind will this be? Print message End_loop

I need help this is Python

Answer 1

Answering only the first question as HOMEWORKLIB guidelines.

The output will be:

We value only integers.
0's are not allowed on test
You can't divide by 0
Wrong type, Programmer error
Check your spelling!!

Explaining each exception

• print(int("four"))
  • the value "four" is a string and cannot be converted to an int. So it raise valueError.
• notZero(0)
  • the function raise a user defined exception MyError, if num == 0
• print(1/0)
  • It raise ZeroDivisionError since we have 0 as the denominator.
• x = 1 + "hello"
  • An integer and string cannot be added. Hence the exception TypeError.
• spellingWord="Banana"\nprint(spollingWord)
  • spollingWord is not defined. So raise NameException. The program catch this exception and executes the corresponding instructions.