Question

Hello,

In Python

Enhance the prior assignment by doing the following

1) Create a class that contain all prior functions

MyLib

# This function adds two numbers
def addition(a, b):
    return a + b

# This function subtracts two numbers
def subtraction(a, b):
    return a - b

# This function multiplies two numbers
def multiplication(a, b):
    return a * b

# This function divides two numbers
# The ZeroDivisionError exception is raised when division or modulo by zero takes place for all numeric types
def division(a, b):
    try:
        return a / b
    # This exception will be raised when the user attempts division by zero
    # Implemented here so if the users input is '0' it will display error that you can't divide by zero
    except ZeroDivisionError:
        print("Error: Cannot divide by zero!")

# This function allows for string manipulation
def scalc(p1):
    string1 = p1.split(",")
    if string1[2] == "+":
        result = addition(float(string1[0]), float(string1[1]))
    elif string1[2] == "-":
        result = subtraction(float(string1[0]), float(string1[1]))
    elif string1[2] == "*":
        result = multiplication(float(string1[0]), float(string1[1]))
    elif string1[2] == "/":
        result = division(float(string1[0]), float(string1[1]))
    return result

# This function returns the results of input values in addition, subtraction, multiplication and division
def allInOne(a, b):
    add = a + b
    subtract = a - b
    multiply = a * b
    divide = a / b

    print('res is dictionary', {"add": add, "sub": subtract, "mult": multiply, "div": divide})
    return{"add": add, "sub": subtract, "mult": multiply, "div": divide}

# This module contains math operation functions
import MyLib


# This is the main function, this is the starting point of execution of the program
def main():
    print("\nWelcome to Calculator!\n")
    # Menu of available math operations for use
    menuList = ["1) Addition", "2) Subtraction", "3) Multiplication", "4) Division", "5) Scalc", "6) All in one",
                "0) Exit\n"]
    # Takes user input to proceed with selected math operations
    while True:
        try:
            print("Please enter your choice to perform a math operation: ")
            for n in menuList:
                print(n)
            menuChoice = int(input("Please input your selection then press ENTER: "))
            if menuChoice == 0:
                print("Goodbye!")
                sys.exit()
            # Checks users input against available options in menu list, if not user is notified to try again.
            if menuChoice > 6 or menuChoice < 0:
                print("\nNot a valid selection from the menu!"
                      "\nTry again! ")
                main()
        # This exception will be raised if the users input is not the valid data expected in this argument.
        except ValueError:
            print("\nError!! Only integer values, Please try again!")

            main()
        # User input to determine input of range a user can work with
        print("Please enter a value for low & high range between -100 & 100")
        lowRange = int(input("Enter your low range: "))
        if lowRange < -100 or lowRange > 100:
            print("Error: ensure input doesn't exceed range of -100 to 100")

            break
        highRange = int(input("Enter your high range: "))
        if highRange < -100 or highRange > 100:
            print("Error: ensure input doesn't exceed range of -100 to 100")

            break
            # Takes user input to perform math operations with input value
        firstNum = float(input("Enter your first number: "))
        secondNum = float(input("Enter your second number: "))
        # Checks users input value is within the given ranges
        while True:
            if firstNum < lowRange or firstNum > highRange:
                print("Error: first number input exceeds ranges, try again!")

                break
            if secondNum < lowRange or secondNum > highRange:
                print("Error: second number input exceeds ranges, try again!")

                break
            # Computes math calculations based on users menu selection
            if menuChoice == 1:
                print(firstNum, '+', secondNum, '=', MyLib.addition(firstNum, secondNum))
            elif menuChoice == 2:
                print(firstNum, '-', secondNum, '=', MyLib.subtraction(firstNum, secondNum))
            elif menuChoice == 3:
                print(firstNum, '*', secondNum, '=', MyLib.multiplication(firstNum, secondNum))
            elif menuChoice == 4:
                print(firstNum, '/', secondNum, '=', MyLib.division(firstNum, secondNum))
            elif menuChoice == 5:
                print('The result of ', firstNum, '+', secondNum, '=', MyLib.scalc(str(firstNum) + ','
                                                                                   + str(secondNum) + ',+'))
                print('The result of ', firstNum, '-', secondNum, '=', MyLib.scalc(str(firstNum) + ' ,'
                                                                                   + str(secondNum) + ',-'))
                print('The result of ', firstNum, '*', secondNum, '=', MyLib.scalc(str(firstNum) + ', '
                                                                                   + str(secondNum) + ',*'))
                print('The result of ', firstNum, '/', secondNum, '=', MyLib.scalc(str(firstNum) + ', '
                                                                                   + str(secondNum) + ',/'))
            elif menuChoice == 6:
                res = MyLib.allInOne(firstNum, secondNum)
                print(str(firstNum) + " + " + str(secondNum) + " = " + str(res["add"]))
                print(str(firstNum) + " - " + str(secondNum) + " = " + str(res["sub"]))
                print(str(firstNum) + " * " + str(secondNum) + " = " + str(res["mult"]))
                print(str(firstNum) + " / " + str(secondNum) + " = " + str(res["div"]))

            # This will ask the user if they want to us the calculator again
            while True:
                reCalculate = input("\nWould you like to try another operation? (y/n): ")
                if reCalculate == 'Y' or reCalculate == 'y':
                    print()
                    main()
                else:
                    print("\nThanks for using calculator! "
                          "\nGoodbye!")
                sys.exit()


main()

Thank you!

Answer 1

Hi,

I have edited the code added a class and optimized code to run with the class.

The required answer is given below in case you face any doubts you can ask me in comments.

main.py

class calculatorClass:
def addition(self,a, b):
return a + b

# This function subtracts two numbers
def subtraction(self,a, b):
return a - b
  
# This function multiplies two numbers
def multiplication(self,a, b):
return a * b
  
# This function divides two numbers
# The ZeroDivisionError exception is raised when division or modulo by zero takes place for all numeric types
def division(self,a, b):
try:
return a / b
# This exception will be raised when the user attempts division by zero
# Implemented here so if the users input is '0' it will display error that you can't divide by zero
except ZeroDivisionError:
print("Error: Cannot divide by zero!")
  
# This function allows for string manipulation
def scalc(self,p1):
string1 = p1.split(",")
if string1[2] == "+":
result = addition(float(string1[0]), float(string1[1]))
elif string1[2] == "-":
result = subtraction(float(string1[0]), float(string1[1]))
elif string1[2] == "*":
result = multiplication(float(string1[0]), float(string1[1]))
elif string1[2] == "/":
result = division(float(string1[0]), float(string1[1]))
return result
  
# This function returns the results of input values in addition, subtraction, multiplication and division
def allInOne(self,a, b):
add = a + b
subtract = a - b
multiply = a * b
divide = a / b
  
print('res is dictionary', {"add": add, "sub": subtract, "mult": multiply, "div": divide})
return{"add": add, "sub": subtract, "mult": multiply, "div": divide}
  

def main():
print("\nWelcome to Calculator!\n")
calculatorObj = calculatorClass()
# Menu of available math operations for use
menuList = ["1) Addition", "2) Subtraction", "3) Multiplication", "4) Division", "5) Scalc", "6) All in one",
"0) Exit\n"]
# Takes user input to proceed with selected math operations
while True:
try:
print("Please enter your choice to perform a math operation: ")
for n in menuList:
print(n)
menuChoice = int(input("Please input your selection then press ENTER: "))
if menuChoice == 0:
print("Goodbye!")
return
# Checks users input against available options in menu list, if not user is notified to try again.
if menuChoice > 6 or menuChoice < 0:
print("\nNot a valid selection from the menu!"
"\nTry again! ")
main()
# This exception will be raised if the users input is not the valid data expected in this argument.
except ValueError:
print("\nError!! Only integer values, Please try again!")

main()
# User input to determine input of range a user can work with
print("Please enter a value for low & high range between -100 & 100")
lowRange = int(input("Enter your low range: "))
if lowRange < -100 or lowRange > 100:
print("Error: ensure input doesn't exceed range of -100 to 100")

break
highRange = int(input("Enter your high range: "))
if highRange < -100 or highRange > 100:
print("Error: ensure input doesn't exceed range of -100 to 100")

break
# Takes user input to perform math operations with input value
firstNum = float(input("Enter your first number: "))
secondNum = float(input("Enter your second number: "))
# Checks users input value is within the given ranges
while True:
if firstNum < lowRange or firstNum > highRange:
print("Error: first number input exceeds ranges, try again!")

break
if secondNum < lowRange or secondNum > highRange:
print("Error: second number input exceeds ranges, try again!")

break
# Computes math calculations based on users menu selection
if menuChoice == 1:
print(firstNum, '+', secondNum, '=', calculatorObj.addition(firstNum, secondNum))
elif menuChoice == 2:
print(firstNum, '-', secondNum, '=', calculatorObj.subtraction(firstNum, secondNum))
elif menuChoice == 3:
print(firstNum, '*', secondNum, '=', calculatorObj.multiplication(firstNum, secondNum))
elif menuChoice == 4:
print(firstNum, '/', secondNum, '=', calculatorObj.division(firstNum, secondNum))
elif menuChoice == 5:
print('The result of ', firstNum, '+', secondNum, '=', calculatorObj.scalc(str(firstNum) + ','
+ str(secondNum) + ',+'))
print('The result of ', firstNum, '-', secondNum, '=', calculatorObj.scalc(str(firstNum) + ' ,'
+ str(secondNum) + ',-'))
print('The result of ', firstNum, '*', secondNum, '=', calculatorObj.scalc(str(firstNum) + ', '
+ str(secondNum) + ',*'))
print('The result of ', firstNum, '/', secondNum, '=', calculatorObj.scalc(str(firstNum) + ', '
+ str(secondNum) + ',/'))
elif menuChoice == 6:
res = calculatorObj.allInOne(firstNum, secondNum)
print(str(firstNum) + " + " + str(secondNum) + " = " + str(res["add"]))
print(str(firstNum) + " - " + str(secondNum) + " = " + str(res["sub"]))
print(str(firstNum) + " * " + str(secondNum) + " = " + str(res["mult"]))
print(str(firstNum) + " / " + str(secondNum) + " = " + str(res["div"]))

# This will ask the user if they want to us the calculator again
while True:
reCalculate = input("\nWould you like to try another operation? (y/n): ")
if reCalculate == 'Y' or reCalculate == 'y':
print()
main()
else:
print("\nThanks for using calculator! "
"\nGoodbye!")
return
main()

Screenshot and Outputs