Question

Figure 1 shows the 5 kg block A slides down the plane with a constant velocity when 0 = 45° a) Draw Free Body Diagram (FBD) and Kinetic Diagram (KD) of block A by showing all the forces. (4 marks) b) Determine the kinetic friction coefficient of the block A. (3 marks) c) Suddenly the handrail was lifted up at B so that the plane angle become e = 60°. Find the acceleration of block A at this instant (3 marks) B Figure 1: Block A slide down on the plane

Answer 1

(6) Given that block slides down the Plane with constant velocity when o=450 Net Force acting on the block along the incline can be given by mgsino - f we know that when block moves at Conetant velocity, aceleration as o when o=45° and kinetic friction of all, N. and N= mgcoso. & ad (mgcoso) – 4 Img cos 45o) m(o) = mgsin 45 - Mmg coses). sinus = le cos45° Mu - Tan 45o = 1. kinetic friction Co-efficient of the blocê À is Me = 1 (Anus. (c) we have not fone arting on block A along the incline al

ma = mg sino - f. mg sinolly (mg cose). ma = > g (sino-Mycose). when 60 and already already we got, Maal g(sin 60°- () cosce"). 9.91( sin co- Cors) 3-5907 m/s2 Acceleration of block n when the handrail is lifted up to O = 60° is a = 3.5907 m/s (An).