Question

Find Voin the given circuit where P = 120 sin(21) V. Please report your answer so the magnitude is positive and all angles are in the range of negative 180 degrees to positive 180 degrees. 0.5 H + Р +1 2H ele ell 2 H vo 0.5 F The value of vo(t) = cos(2t+ 1).

Answer 1

Given circuit is 0.SH 2H 0,5F لروين + No 2H Р P= 120sin(t) v ws2 rad/sec. jXL = jwL j*c - jwc network into the phasor domain. jut=j.2 1/2 = je above Transform the I22 z = -j.22 j. 2. 1 / 2 120 Lov ejus jus Network is in Phasor Domain By KVL in Phasor Domain , 12020° = jy Is -j Iz 0 = j Iz -j4 I 1 solving Equations 8 and ②, ju Iz - j Iz = 12010° -j4 Ia -j Iz 120409 2_90 0 - 2j Iz = 120 Loº 120109 120L0° → I2 -2j 2/270° 60/6-1-90) Iz = 60 (+90° Amp - I2 = Vo Iz. (-)) = Vo = [240] [-j] → V. = 120 LC 120L09 → V. = 60 Lov vo = 60 sin (2+) v =>Vo = 60 cos(2t -90°) V