Question

1a. A cockroach of mass m lies on the rim of a uniform disk of mass 9.00 m that can rotate freely about its center like a merry-go-round. Initially the cockroach and disk rotate together with an angular velocity of 0.456 rad/s. Then the cockroach walks halfway to the center of the disk.
(a) What then is the angular velocity of the cockroach-disk system?
(b) What is the ratio K/K₀ of the new kinetic energy of the system to its initial kinetic energy?

1b.

The figure shows a rigid structure consisting of a circular hoop of radius R and mass m, and a square made of four thin bars, each of length R and mass m. The rigid structure rotates at a constant speed about a vertical axis, with a period of rotation of 2.0 s. If R = 1.2 m and m = 5.1 kg, calculate the angular momentum about that axis. Rotation asis DOI

Answer 1

P.S : Please do give a thumbs up since we as an expert take pain and take our time out by typing answer in lucid language and putting best of our knowledge at your doorstep.
Thank you

m Tinitial IMR² 2 + MR2 O = IMR? I fried 1) IMR2 2 MRR 19MR? 4 Conserve angular mementum | ART X 0.456 19 MRE 19 meter x49 find Warial = 0.528 rad/sec (I wa) final (I602mempel 19 X O.5282 1.1578 K ko 4 x 0.4562 1.158 *M