Question

The emis in the figure below are &1 = 5.00 V and Ez = 18.0 V. The resistances are Ri = 15.50, R2 = 31.5 Q, R = 47.52, and R4 = 59.0 2. Find the magnitude of the current in each resistor when the switch is in the following states R w RA SR E2 S R3 (a) open 11 = .19 12 = .19 13 = .19 1 = 0 A (b) closed 11 = x Your response differs from the correct answer by more than 10%. Double check your calculations. A IM Your response differs from the correct answer by more than 10%. Double check your calculations. A 13 = Your response differs from the correct answer by more than 10%. Double check your calculations. A x 14 = Fatar a unha differs from the correct answer by more than 100%. A

Answer 1

Ry BRI R3 Rz ہلا Why ic=0.2142 A=iR Sol:- given 8, = 5V, E2 = 18 v R, = 15,52 R₂ = 31.52 R3=47.52 Ry = 592 EL u A) switch open:- → As this part is done, will go with part 'B'. B) switch closed :- As 9 : ERIK Elt la iR3 E,- (Ri-ia Ry=0 >>5-15.5ic-59 19 = 0 Now apply kvL for loop ③ &z - ib (Rg+R2) - ICR, = 0 >18-16 (47.5+51.5)-15.58 = 0 => 18-79 86-15.5ic=0 → we also have latib-ic=0 Now by solving abone equs og and ia = 0.0284 A = lry i6 = 0.1858 A = 1R3=R2 is - Now apply KUL for loop A, Tio B ->Now 2 we get Answers :- parts:- I, 0.214 A Iz = 0.1858 A Iz = 0.1858 A Iy = 0.0284 A Hope will get VOTE