Question

I am creating a recursive function in c++ and have the following code so far. However, can you help me fix it so that it doesn't crash when negative numbers are entered. If negative numbers are entered i want to let the user know negative numbers are not accepted and to try again

#include <iostream>

using namespace std;

int multiplication(int x, int y)
{
int sum = y;

//if value of x is 1, then result of x*y will be y
if (x == 1)
return sum;
//if x geater than 1 then call the multiplication function and add eat iteration
else
sum = sum + multiplication(x - 1, y);
return sum;
}

int main()
{
//variables
int x, y, multi;

cout << "Enter x";
cin >> x;

cout << "Enter y";
cin >> y;

//multiplication function
multi = multiplication(x, y);
cout << multi;

}

Answer 1

tart here X *negative.cpp X #include <iostream> using namespace std; 1 2 3 4 5 6 7 8 int multiplication (int x, int y) { int sum = y; 9 10 11 12 13 14 15 16 17 1//if value of x is 1, then result of x*y will be y if (x == 1) return sum; ///if x deater than 1 then call the multiplication function and add eat iteration else sum = sum + multiplication (x - 1, y); return sum; int main() ///variables int x, y, multi; cout << "Enter X cin >> x; cout << "Enter y : "; cin >> Yi while (x < 0 || y < 0)/// While loop for finding negative numbers TE { 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 cout<<"You are entered Negative numbers " <<endl; cout<<"Please enter Positive numbers, of x and y "<<endl; .. cout << "Enter x cin >> x; cout << "Enter y : "; cin >> Yi نسية ///multiplication function multi = multiplication(x, y); cout << multi;

Out Put: D: 19891A0224\negative.exe Enter x : -10 al Enter y : -20 You are entered Negative numbers tPlease enter Positive numbbers of x and y Enter x : 10 Enter y : 20 200 Process returned 0 (0x0) execution time : 28.739 s Press any key to continue. u i

The Program Code is :

#include <iostream>

using namespace std;

int multiplication(int x, int y)
{
int sum = y;

///if value of x is 1, then result of x*y will be y
if (x == 1)
return sum;
///if x geater than 1 then call the multiplication function and add eat iteration
else
sum = sum + multiplication(x - 1, y);
return sum;
}

int main()
{
///variables
int x, y, multi;

cout << "Enter x : ";
cin >> x;

cout << "Enter y : ";
cin >> y;
while(x < 0 || y < 0)/// While loop for finding negative numbers
{
cout<<"You are entered Negative numbers " <<endl;
cout<<"Please enter Positive numbbers of x and y "<<endl;

cout << "Enter x : ";
cin >> x;
cout << "Enter y : ";
cin >> y;

}

///multiplication function
multi = multiplication(x, y);
cout << multi;

}

Dear Student: This Program given the solution for your question Still you have any query? Feel free to ask in comment section Thank You