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Part A During a very quick stop, a car decelerates at 7.40 m/s. What is the angular acceleration of its 0.280-m-radius tires,

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Peltas we know that, id=0 The angular acceleration of the car is, de-a ४ =- 7.40mis 2 0.280m :-26.42 radls? = PastB;. u knowPart Ei The initial Speed, Vi= 60; 7 Vi = 90% 0.280 25.2 misec Posto: The distance toavelled , d = Vitt hat? = 2512 X3.40 +0.

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