Question

1. Use the protractor to measure the incident angle at the dispersion interface 0i, as well as the dispersion angles 0, for red light and 68 for blue light as seen in Figure C7. Record measurements below for all angles in terms of degrees (). Ai = 20° A = 27° θε 29° 2. Based on the two different dispersion angles of red light and blue light, which color traveled faster in the acrylic rhomboid? How do you know? The blue light, because it had a bigger angle. 3. Use Snell's Law to calculate the index of refraction for the two different colors of light (n for red and ng for blue) in the acrylic rhomboid. Assume that the light ray basically remains a single white light ray (does not disperse much) as it travels through the rhomboid, and the index of refraction for air is 1. n = 0.75 n = 0.70

a better picture of the questions I need answered.

Answer 1

v_r = c / n_r = 3e8 / 0.75 = 4e8 m/s

though speed of light cannot be more than 3e8 m/s but this is what I got based on your results

________________

v_{$\beta$ =} 3e8 / 0.70 = 4.28e8 m/s

_______________

wavelength in any medium

$\lambda$ = $\lambda$ _o / n

where $\lambda$ _o is wavelength in air