Question

Part B Lab Go to PhET website. Click on Simulation/Physics. Under Physics, choose Light & Radiation. Under Light & Radiation, Bending Light is the 6th simulation (Location might change. A to Z search.). Click to run the Bending Light/More Tools Complete Data Table with Bending Light/More Tools Simulation: Basic Operation for More Tools Simulation: Place check marks on Ray, Normal, and Angles. Keep the default setting Material 1 (above surface) index of refraction as air nt = 1.000 and Material 2 (below surface) index of refraction as glass nam. Adjust incident wavelength of light to l = 700 nm. Press the Red Button of the light source. Using the default incident angle e, = 45°, record the refracted angle and index of refraction nam (under Material 2) to Data Table Test and understand all functional tools on screen You must practice figuring out what is the best way to complete the measurement. Data Table 1: Measure Index of Refraction Keep incident angle 0: = 45°. Vary incident wavelength (nm). Measure refracted angle 02 (™) and index of refraction nam in medium of glass. Calculate na by Snell's law: n2 = nisine/sine. Calculate speed of light in glass by 03 = c/n (in unit of c, Ex. ne 1.500, 0 = c/1.500 = 0.667c), c is speed of light in vacuum: c = 2.998 x10 m/s. Attach a Screenshot of 700 nm Measurement from the Simulation to Lab Report 21 (nm) 02 (Ⓡ) n2M n2 = nisine/sing2 12 = c/n (c) 700 500 400 . Question: From data 2 - 700 nm in air, find the wavelength 1, and speed us in 2nd medium. Calculate frequency in air and glass for 21 - 700 nm. When the incident 2, is changed, what quantities will change in 210 medium? .

Answer 1

For 2 = 700 nm 02 = 28.2 n2m = 1.499 Using the Snell's law: nisine (1) sin(45) sino sin (28.2) n2 = 1.49636 с V2 == = 0.668c n2 n2 = 45.0° 45.0 28.2° For 2 = 500 nm 02 = 28° n2M = 1.507 Using the Snell's law: nisine (1) sin(45) sin sin(28) n2 = 1.5062 V2 = - = 0.6639c n2 n2 = с For 2 400 nm 02 = 27.8° n2m = 1.516 Using the Snell's law: n sine (1) sin(45) n2 sine sin (27.8) n2 = 1.5161 с V2 = 0.6596C n2 Question: 11 700 12 467.8 nm n2 1.49636 The frequency is: с 3 x 108 f = 4.286 x 1014 Hz 2 700 X 10-9 The wavelength speed changes in medium 2.