Question

Suppose that daycare costs are normally distributed with a mean equal to $10,000 a year and a standard deviation equal to $2,000. Find the probability that the daycare centers will cost between $8,000 and $ 12,000? O 0.6827 O 0.3413 O 0.7324 O 0.8257

Answer 1

solution:- option: 0.6827

explanation:-

given that mean = 10000 , standard deviation = 2000

formula

z = (x-mean)/standard deviation

=> P(8000 < x < 12000)

=> P((8000-1000)/2000 < z < (12000-10000)/2000)

=> P(-1 < z < 1)

=> 0.6827

note:- z values from standard normal distribution table