Question

Obtain the period of vibration of the system shown in Figure 1. The blue block has a mass of 58 kg and is pushed down 1 m from its equilibrium position and it is then released. This system is subjected to a force F of magnitude 12 N, sufficient to cause deformation δ. Determine its vibration period

k1=4,495 N/m

k2=6,242 N/m

Obtenga el periodo de vibración del sistema mostrado en la Figura 1. El bloque azul tiene una masa de 58 kg y se empuja 1 m hacia abajo desde su posición de equilibrio y este luego se suelta. Este sistema se somete a una fuerza F de magnitud 12 N, suficiente para causar una deformación S. Determine su periodo de vibración (-). ki k2 Figura 1 k1=4,495 N/m k2=6,242 N/m

Answer 1

Solution : According to the given data, the following as the solution. Given that 2 ki The is m= 58 58 kg may i's Fz 12 N. force of magnitude ki 4, 495 N/m N/m K2= 6, 242 Here, Kitk2 series connection) KK2 1 Keg 4 + 1 4 kes 2) 4495 X6 242 ul Kes = kik2 Kitkz 4495+ 6242 2 613. IS N/m )

In which the maximum de flection on amplituck Xmax = 1m For forced vibration without damping ㄷ x mar m[wntwor] kes wn -> = 12 N 2613 - 18 58(45.05498 wr 58 45.0549 red's 11 = 12 wr => *{(45 -5.0549)" ] = (45.0549)_wv = 1 12 = 0. 2068 58 = 4) » -> (45.0549) - 0.2068 rad is W = 45.0526 > Time period of the the vibration (T) = 2 T शा 45.0526 لا = 0.1393 see

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