Question

Name: Written Assignment H (Sections 6.1-CI, 6.1-HT, 6.2-CI, 6.2-HT) STA 270: Applied Statistics 1. In a random sample of 1500 U.S. adults, 780 of them are "Thriving" which is defined as rating their current life as 7 or higher on a 10 point scale and rating their future life as 8 or higher on a 10 point scale. Using the methods of Section 6.1-CI (statistic + 2*(SE)), find and interpret a 99% confidence interval for the proportion of all U.S. adults who are thriving (based on this definition). Show all calculations.

Answer 1

A random sample of 1500 u.s. adults , 780 of them thriving i.e. De-780 are n = 1500 ol 780 1500 = 0.52 n 99. confidence interval for the proportion of all us. adults who aro thriving ſ + 2 (SE) È E ZH2 (م-1م 0.52 + 70.01 0.52 (1-0.52) 2 1500 > 0.52 I 70.005 (10.0001664) 0.52 + 2.58 (0.0128996) -> 0.52 +0.033281 (0.486719, 0.553281) N (0.4867,05533) 99. confidence interval for the proportion of au u.s. adults who are triving is 0.4867 to 0.5533 I uterpretahon! We are 997 confident that proportion of au Us adults who are troiving in the population is ce between 0.4867 and 0.5593