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25cm 100cm m, m2m1=13kg m2=5kg

At what specific distance from the suspension line should we place the third ornament if the third ornament is 10kg?

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250mt 100cm- M2 my of mag m, = 13 kg m2 = 5kg Torque of mig about suspension point is Cm, = migxescom > cm, =(13x9.8 x0.25)NmFor equilibrium, Ema Emittma 31.85+ Mzgx = 49 10x9.8x2 = 49-31.85=17, 15 17.15 >x m p=0.175m 98 Slx= 17.5cm

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