Question

A cyclic process A cylinder contains 0.50 mol of ideal gas at 27.0 °C. First, the gas is heated to 127.0 °C while the pressure is maintained constant at 1.0 atm by a frictionless piston. a. How much work is done by the gas in this process? b. On what is this work done? c. What is the change in internal energy of the gas? d. How much heat was supplied to the gas? Second the gas is cooled back to 27.0°C while the volume remains constant. e. How much work is done by the gas in this process? f On what is this work done? g. What is the change in internal energy of the gas? h. How much heat was supplied to the gas? Third, the gas is returned to its original state via an isothermal process. i. How much work is done by the gas in this process? j. On what is this work done? k. What is the change in internal energy of the gas? 1. How much heat was supplied to the gas? m. Sketch the complete cycle on a PV diagram.

General Physics

Answer 1

using the formula PV = nRT p=latm = 1.01x105 N/m² n = 50 mol, R = 8.31 3 /mol-k. T = 273 +27 = 300k MRT (.50) (8.31) (30) = v= P 1.0x105 = .012 m² Now gas at constant pressure ń to heated to 127°C using the formula, 3 V V V = .012m Ti Ta 273+27 = 3 vok = 4ook T = 273+127 Vy=2 012 360 400 400 x .012 300 2 = = .016 m? gas work done by the (W) - POV =P(V₂-v) 1.01x105 (016-012) Imle 40 4 Joule. Am work done by the gas 404 Joule ( increasing an increasing the temperature volume is So work done by the gas i positive This work done on the piston.

not given here gas atomicity is So we consider, gas n monoatomic Cu = 32, 3/mol-k, Change in internal energy at constant pressure AU = nydt R = 8.31 3 /mol-k, n= somol dTo change in temperature T2 - Ti = 400 - 300 = 1 rok Au = (050) (3R) (100) Junie (152) ( 3X8.31) (100) onu 623.25 Jonle. An - 623.25 Tonle. Change in internal energy we know ♡ au tW of = heat supplied to the gas. 4 h = 623.25 onke 4 04 Joule Q 623.25 +404 Joule 1027, 25 Jonle An heat supplied to the gas = 1027.25 Junk.