Answer
Small flower × Large flower........... parents
SS × ss
S s................ Gametes
Ss ( Small flower) ............. F1
Ss X Ss ...................selfing
| S | s | |
| S | SS ( Small flower) | Ss (Small flower) |
| s | Ss( Small flower) | ss ( large flower) |
Phenotype = 3:1
Genotype= 1:2:1
Explanation:
a. When we cross a small flower with large flower where the small flower is dominant and large flower is recessive. So the genotype of the parents are
Small flower: SS
Large flower: ss
The genotype of the F1 offspring are Ss ( small flower)
b. In F2 generation
The genotype ratio is
1:2:1 ( SS : Ss: ss)
The phenotype ratio is
3:1 ( Small flower: large flower)
I need answers line that A pure line of pea plants, Pisum hypothecalis possesses small flowers....
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