Question

The wire in the figure carries a current of 2.22 A and has a length of 4.66 m. It is immersed in a magnetic field whose magnitude is 1.77 T, which points at an angle 8 = 42.2º relative to the wire. What is the magnitude of the magnetic force on the wire?

Answer 1

We know,

F = B×i×L×sin

here, F = force on the wire

B = magnetic field= 1.77 T

i = current= 2.22 A

L = length of the wire= 4.66 m

= angle between the wire and the magnetic field= 42.2°

Now, F = 1.77×2.22×4.66×sin(42.2)

=> F = 12.3 N (approx)

So the force on the wire is 12.3 N

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