Calculate the E°cell for the following reaction:
Cu2+ (aq) + Ni (s) → Cu (s) + Ni2+ (aq)
A) (-0.59 ± 0.01) V
B) (-0.09 ± 0.01) V
C) (0.59 ± 0.01) V
D) (0.09 ± 0.01) V
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What is the proper line notation for the following reaction?
Cu (s) + 2Ag+ (aq) → Cu2+ (aq) + 2Ag (s)
A) Cu2+ | Cu || Ag | Ag+
B) Ag+ | Ag || Cu | Cu2+
C) Cu | Cu2+ || Ag+ | Ag
D) Ag | Ag+ || Cu2+ | Cu
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Based on the table of standard reduction potentials, which of the following would be the strongest reducing agent at 298K
A) Zn2+ (aq)
B) Ni (s)
C) F- (aq)
D) Cu (s)
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Calculate the E°cell for the following reaction: Cu2+ (aq) + Ni (s) → Cu (s)...
Calculate the E°cell for the following reaction: Cu2+ (aq) + Ni (s) → Cu (s) + Ni2+ (aq) A) (-0.59 ± 0.01) V B) (-0.09 ± 0.01) V C) (0.59 ± 0.01) V D) (0.09 ± 0.01) V --------------------------------------------------------------------------------------------------------- What is the proper line notation for the following reaction? Cu (s) + 2Ag+ (aq) → Cu2+ (aq) + 2Ag (s) A) Cu2+ | Cu || Ag | Ag+ B) Ag+ | Ag || Cu | Cu2+ C) Cu |...
Consider the following half-reactions: Half-reaction E° (V) Ag+(aq) +e → Ag(s) 0.799V Cu2+(aq) + 2e → Cu(s) 0.337V Mg2+(aq) + 2e —— Mg(s) -2.370V The strongest oxidizing agent is: enter symbol The weakest oxidizing agent is: The weakest reducing agent is: The strongest reducing agent is: Will Mg(s) oxidize Ag(s) to Ag+(aq)? V Which species can be oxidized by Cu2+(aq)? If none enter none. Consider the following half-reactions: Half-reaction E° (V) 2Br (aq) 1.080V Br2(1) + 2e — Ni2+(aq) +...
electro Calculate the E°cell for the following reaction: Cu2+ (aq) + Ni (s) → Cu (s) + Ni2+ (aq)
Calculate the Ecell value at 298 K for the cell based on the reaction: Cu(s) + 2Ag+ (aq) → Cu2+ (aq) + 2Ag(s) where [Ag+] = 0.00350 M and [Cu2+] = 7.00x10-4 M. The standard reduction potentials are shown below: Ag+(aq) +e → Ag(s) E° = 0.7996 V Cu2+ (aq) + 2e -→ Cu(s) E° = 0.3419 V 2nd attempt Ecell = V
Using the following metal ion/metal standard reduction potentials to calculate the Ecell for Cu2+(aq) + Cd(s) ------> Cd2+(aq) + Cu(s) Cd2+(aq)/Cd(s) Zn2+(aq)/Zn(s) Ni2+(aq)/Ni(s) Cu2+(aq)/Cu(s) -0.40V -0.76 V -0.25V +0.34V
can you answer questions 7,8,9,10
Question 7 (10 points) ✓ Saved (7) For a galvanic cell notation: (-) Mg/Mg2+ (aq) // Cu2+ (aq) / Cu (+). which of the following is fully correct? (a) Mg2+ is oxidized to Mg, and Cu2+ (aq) is reduced to Cu O (b) Mg2+ is reduced to Mg, and Cu2+ (aq) is oxidized to Cu (c) Mg is oxidized to Mg2+, and Cu²+ (aq) is reduced to Cu (d) Mg is reduced to Mg2+, and...
a Cu(s) + 2Ag+ (aq) → 2 Ag(s) + Cu2+ (aq) Redox? Oxidizing Agent Reducing Agent Substance Oxidized Substance Reduced b HCl(g) + NH3 (g) → NH4Cl(s) Redox? Oxidizing Agent Reducing Agent Substance Oxidized Substance Reduced c SiCl4 (l) + 2H2O(l) → 4HCl(aq) + SiO2 (s) Redox? Oxidizing Agent Reducing Agent Substance Oxidized Substance Reduced d C14 (1) + 2Mg(s) + 2MgCl2(8) + Si(s) Redox? Oxidizing Agent Reducing Agent Substance Oxidized Substance Reduced e Al(OH)4-(aq) → AIO2- (aq) + 2H2O(l) Redox? Oxidizing Agent Reducing Agent Substance Oxidized Substance Reduced
Given the following reaction, Cu2+(aq) + Zn(s) → Cu(s) + Zn2+(aq) E° = 1.10 V Use the Nernst equation to calculate the cell potential for the cell described with standard line notation below. Zn|Zn2+(0.5038 M)||Cu2+(0.3981 M)|Cu Units are not required. Report answer to three decimal places.
A galvanic cell consists of a Cu(s)|Cu2+(aq) half cell and a Zn(s)|Zn2+(aq) half-cell connected by a salt bridge. Oxidation occurs in the zinc half-cell. The cell can be represented in standard notation as Cu(s)|Cu2+(aq)|Zn(s)|Zn2+(aq) Zn(s)|Zn2+(aq)||Cu(s)|Cu2+(aq) Cu2+(aq)|Cu(s)||Zn(s)|Zn2+(aq) Zn(s)|Zn2+(aq)||Cu2+(aq)|Cu(s) Zn2+(aq)|Zn(s)||Cu(s)|Cu2+(aq) A,B,C,D?
Calculate the cell potential for the reaction below when the concentrations of ions are: [Ag+ ] = 0.010 M and [Cu2+] = 0.750 M, at 25 °C. Cu(s) + 2Ag+ (aq) --> Cu2+(aq) + 2Ag(s) Given the standard reduction potentials: Cu2+(aq) + 2e– → Cu(s) Eϴ = 0.34 V Ag+ (aq) + e– → Ag(s) Eϴ = 0.80 V (A) 0.35 V (B) 0.44 V (C) 0.46 V (D) 0.48 V (E) 0.57 V