Question

The base sunflower population has a mean of 100 days to flowering. Two parents were selected that had a mean of 70 days to flowering. The quantitative trait days to flowering has a heritability of 0.6. What would be the mean of a population derived from crossing these two parents?h2-R/S 30 72 O 82 O 18

Answer 1

Hello, Today we are are by many Solution going to discuss about question related to quantitative traits Quantitative trails phenotype that are controlled alleles and t have cumulative affect And environmental factors also depend quantitative traits. Q- h here, the mean the base sunflower population 100 days. And the parents with days to flowering are taken. And the here And the heretal heretability on the of Oos 100 mean of to is 0.6 o ale have to from crossing find the the mean mean of a the of a population derived from parents giver

o the O is ha=0.6. heritability o the equation for heritability &a is ha. Rfs o the value for turitability is already given and for that is 0.6. cord o R=has The so the selection differential 22 is the heritabi heritability R a) selection response By finding the selection find population from crossing given . can response, wel the mean mean of the of

h2.0.6 or=h2g where Sa mean and base mean. difference between the selected parents and base pogrulation Base population mean is 100, And the mean selated parents . 5=(70-100) -) -30 of Pcs to o R = haus 0.6 X-30 R = -18 days days

number the new the population mean. By subskaiting the selection response from population mean we can find population So the new population mean is 100-182782 days. Po option (c) sa 'is cortet. new population flowering 821 mean is The new days to Thank you

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