A proton, moving with velocity v=-235x+666z m/s encounters a magnetic field B=3.25z uT. What is the radius of the circular part of the proton's trajectory?

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A proton, moving with velocity v=-235x+666z m/s encounters a magnetic field B=3.25z uT. What is the...
A proton, moving with velocity v = -234 +6662 m/s encounters a magnetic field B = 3.252 UT. What is the radius of the circular part of the proton's trajectory?
A proton, moving with velocity = -234 + 6662 m/s encounters a magnetic field B = 3.252 uТ. What is the radius of the circular part of the proton's trajectory?
Question 15 6.25 pts A proton, moving with velocity ✓ = –234+ 6662 m/s encounters a magnetic field B = 3.252 u T. What is the radius of the circular part of the proton's trajectory?
A proton with v = 450 m/s is moving through a region in which the magnetic field is B = 2.3 T. If the magnitude of the force on the proton is 6.9 10-17 N, what angle does the proton's velocity make with ? (Enter the smallest possible angle.)
a proton is moving with speed of 5.0x10^18 m/s the proton encounter a magnetic field of 0.82T and whose direction makes an angle of 30.0 degrees with respect to the proton's velocity. determine the magnitude of the force on the proton Newt. assume the charge of a proton is 1.6x10^-19 C
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Question 13 3 pts A proton moving at 7x109 m/s through a magnetic field of magnitude 26 T experiences a magnetic force of magnitude 6.9x10- N What is the angle between the proton's velocity and the field? O 6.2 44.99 13.7 76.39 None of the above