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94.0 cm?, and the material is copper. If TH = 109°C, TC Consider the slab shown in the figure below. Suppose that L = 26.0 cm

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  1. L = 25 Сю - о. 26 mm 2 A gyan co.oo99 - T, Tos°C Т - 13.0°C k=yol w/mk Н- KA(In-T) L - Чо) xoroo94 x (Io9 - 13) О: 26 = 13 91
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