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Captain Ralph is in trouble near the sunny side of Mercury. The temperature of the ship's...

Captain Ralph is in trouble near the sunny side of Mercury. The temperature of the ship's hull when he is at location (x, y, z) will be given by T (x, y, z) = e^(−x^2 − 2y^2 − 3z^2), where x, y, and z are measured in meters. He is currently at (1, 1, 1).

If the ship travels at e9 meters per second, how fast (in degrees per second) will the temperature decrease if he proceeds in that direction?

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