Question

Ozone Decomposition: Ozone formation is faster during the day due to the action of sunlight on NO, molecules. Thus, 0,() accumulates in the troposphere and its concentration peaks sometime in the afternoon. During the night, orone reacts with NO(g) according to the following reaction: NO(g) + O2(g) - NO(g) + O2(b). This is a single step process with an activation energy - 12.5 kJ/mol and a AH--199.5 kJ/mol. PPS 5. Build potential energy diagram that represents the transformation of reactants to products. Indicate on the diagram the activation energy and the heat of the reaction for this process. Hour 6. Derive the rate law for this process and predict the effect on the rate of reaction of doubling o concentrations. 7. Estimate how many times slower this process is at 0 °C than at 25°C. This reaction is product-favored at 25 °C. Estimate the temperature at which it becomes reactant-favored.

Answer 1

coll A Horton NO(g) + Oz (g) NO2 (g) + O2 (9) Ea = 12.5 kJ/mol A Hram -1995 Kamol ( change of enthalpy of reaction is eve So, reaction is exother mic " Reaction So there ir no intermediate stel is single step reaction foresent. Only transition st (Tsolis foresent Tos Ea 12.5 kJ/mol K Noton (Energy) AH -199. Ski Anul ta Nonton Reaction coordinate coll Now / In single step reaction order of the reaction is eanual to and ecularity of the reaction. molecul arity in the number of molecules that react inssingl step reaction The molecular arity of stoichiometric coeffi cient of reactants in the the one step ( element reaction, any le in the sum

= 12 SOG I/mol the rea of no of So, when [ond is doubled Here in the reaction eactants are No 4 Oz. The roum of evefficient of no foz is equal to equal to (1+i)=2 The order reaction will be here a the rate will be : Rate=k [no] [03] where rate contant when, [no] = contant then Rate a [03] then Rate honius eanation we get ) kal Ti (ki R where, herfectively Ea = Activation energy RE Gar content = 8B14 no yon ده سال e of doublecl. From Aro hanius eanation HI Ea en T .[ k, fk2 are rate contant at Ti Kelvin & Tz Kelvin & Blu Motik Eaz =2986 12.5K here, I = 0 .ca 273K , TL = 2500 enke soof/mys x [ J/mol 1000 268] *tx 273 12 8.314 =) en (ka) 0.462 TKI 1.59 e o 462 1156 0.63 ki/kr 1.59 At ove this process is slowen 0.63 timer than at nsoc