Question

You should be able to relate the initial wavelength, the final wavelength, and the angle involved in the Compton scattering event. The momentum of the photon is directly related to its wavelength. Combine the two relationships to find the initial wavelength.

If 28.0%28.0% of the momentum is lost, how much remains?

Use these constants to answer the question.

?eℎ?=9.11×10−31 kg=6.63×10−34 J⋅ s=3.00×108 m/s

A photon collides with an electron, and is scattered in a direction 155 from its original direction. If the photon loses 28.0% of its momentum in the process, what was the photon's initial wavelength? wavelength: m

Answer 1

Sal@ = 0.28 Soll 0 21550 Griven Data Ploss Р Using the relation h. (1-lose) d-di mec i di = 6.626x10-34 (1-6, 155) 9.1*10-31x3x108 da-di = 4.62x10-12 m As we know, Momentum p=h .P=(-0.28) Po p=0.72 Po als = 0.72 h di 4 = di 0.72 put in a

di = 4.62 XTC Here intense de -11.88 x 10+2 elegt with. Initial حسن