Question

The cable that suspends the 210 ko mass wraps over the pulley with center and ties off at E. The pulley has negligible radius. (Assume that the +x-axis is to the right a calculations-Including answers submitted in WebAssign.) 210 kg 3.2 m 2.4 m 2.4 m Determine the force that pin A exerts on bar ABC, and determine member force BD. (Enter forces in kilonewtons.) ĀK magnitude KN direction -Select- Ā, magnitude KN direction -Select- Foo magnitude KN sense -Select- Determine the force that pin C exerts on bar ABC. (Enter the magnitude in kilonewtons and the direction in degrees counterclockwise from the +x-axis.) magnitude KN direction counterclockwise from the +x-axis

Answer 1

Solun B A 3.2 1 Blokg 2.4m 2.4m assuming value of specific gravity g= 9.81 m/8ec² tension will be constant 80 same Cable i FBD af Cable mass = 210 kg (W) weight = 210x G.81 = 2.0601 KN NT "T=W= 2:0 601 KN 2lokg VW ABC B 2.4m A 2.4m a Ax TAY T tena = 3.2 T Sina=0.8 taking moment about a cosa = 0,6 FBD sind 824 + T sina x 4.0 + Tx4.8= 0 FBD = - 9.27045 KN Compression Ay = FBD sina + Tsina+T = - 3.70818 kn An = FB D Cosat Tosa = - 4.32621 KN

they Ay = -3.70818 KN ( 4.32 621 KN FBD = -9. 270 45 KN (compression)