Question

Consider the following circular array queue. Indicate what would be printed when executing the following code (assuming array is the variable containing the elements): count 5 front XHL se 2 rear 0 1 2 3 4 N int t = front; for (int q = 0; q < count; q++) { System.out.print(array(q) + t = (t + 1) % array.length; } ");

Answer 1

Here , t = front = 2.

The for loop will run from q = 0 to 4 and will increment in steps of one at a time.

Inside the for loop, the value of t is changing but that is not changing or affecting the print statement. Thus output is independent on the value of t.

In each iteration, the value printed is array[q]

When q=0, value printed is array[0]=X.

When q=1 , value printed is array [1]=H

Thus all the array content is printed in order.

Thus the output is :

X H L S P

If you have any questions comment down and please? upvote thanks....