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Consider the following code. Assume that the array begins at memory address Ox200. What is printed by the following code. Ass

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Answer #1
iptr is the address of array a
So, iptr is 200

iptr + 1 
= 200 + 1 * sizeof(int)
= 200 + 1*4
= 200 + 4
= 204

So, output of the code is
204

Answer

204

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