Question

C PROGRAM

The following is code prints the current activation record number, the memory address of the current array, followed by the estimated size of the current activation record as a distance between the current array address and the array address from the previous activation record. I need it to run until a segmentation fault occurs and also it must print the estimated size of the runtime stack as a product of the size of current activation record and the total count of activation records so far.

(Please help if you can)

#include <stdio.h>
#include <stdlib.h>
#define SIZE 1000

void f1(){

char values[SIZE];
static int n = 0;
long int addr = (long int )&values[0];
static int i=0;
n++;
i++;
printf("Call #%d",n);
addr = (long int )&values[n];
printf(" at %p\n",addr);
printf("AR size #%d",n);
printf(" is : %d\n",((long int)&values[n] - (long int)&values[n-1]));
}

void main()
{
for (int i=0; i<=10; i++)
{
f1();
}
for (int i=0; i<=100000; i++)
{
f2();
}

}

Answer 1

include <stdio.h>
#include <stdlib.h>
#define SIZE 1000

void f1()
{
int x;
char values[SIZE];
static int n=0;
values[n]=n;
char *addr;
static int i=0;
addr=&values[n];
n++;
i++;
printf("Call #%d",n);
addr = &values[n];
printf(" at %p\n",addr);
printf("AR size #%d",n);
printf(" is : %p\n",(&values[n]-&values[n-1]));
x=sizeof(addr)*n;
printf("Estimated Size of Runtime stack :%d\n",x);
}
void main()
{
for (int i=0; i<=100000; i++)
{
f1();
}
}

/*Segmentation fault occurs when we try to access that part of the memory which is not accessible to us and is allowed for reading purpose only.

So what i did above is i filled whole array with the values of n and when it becomes full we tried to access that part of memory which is not accessible to us because we declared size of array 1000 so this much memory is accessible to us and trying to access more will result in segmentation fault(core dump).*/