Question

Homework Part 1 Write a C program that declares and initializes a double, an int, and a char. You can initialize the variables to any legal value of your choosing. Next, declare and initialize a pointer variable to each of the variables Using printf), output the following: The address of each of the first three variables. Use the "Ox%x" format specifier to print the addresses in hexadecimal notation The value of each variable. They should equal the value you gave them The memory size in bytes of each variable. Use the C "sizeof()" operator to get this information. I. 2. 3. Homework Part 2 Add code necessary to print out the address of the variable 'x' in function ptrLab1, and the variable 'y' in ptrLab2(). What do you notice? Can you explain what you are seeing? #include <stdio.h> void ptrLab1 (int xval) int x; x = xv al ; Add the code to print the address & value of x here void ptrLab2(int dummy) int y Add the code to print the address & value of y here int main (void) ptrLab1(7); ptrLab2(11); return e;

Answer 1

Part 1

######

#include<stdio.h>

int main(){
   //variable declaration
   double a=10.2;
   int b=2;
   char c='a';
  
   //pointers
   double *p1=&a;
   int *p2=&b;
   char *p3=&c;
  
   //printing the address of variables in hex
   printf("Address of a=0x%x\n",&a);
   printf("Address of b=0x%x\n",&b);
   printf("Address of c=0x%x\n",&c);
  
   //printing the value of variables
   printf("Value of a=%f\n",a);
   printf("Value of b=%d\n",b);
   printf("Value of c=%c\n",c);
  
   //printing the value of pointers which is the address of variables it points
   printf("Value of pointer p1=%d\n",p1);
   printf("Value of pointer p2=%d\n",p2);
   printf("Value of pointer p3=%d\n",p3);
  
  
   //printing the size of variables
   printf("Size of a=%d\n",sizeof(a));
   printf("Size of b=%d\n",sizeof(b));
   printf("Size of c=%d\n",sizeof(c));
  
   //printing the size of pointers
   printf("Size of pointer p1=%d\n",sizeof(p1));
   printf("Size of pointer p2=%d\n",sizeof(p2));
   printf("Size of pointer p3=%d\n",sizeof(p3));
   return 0;
}

//##################### PGM END ##################################

OUTPUT
#######

C:\UsersJijinAVADocuments\DevC++_Workspace\Program1.exe Address of a-ΘΧ62feθθ Address of b-0x62fdfo Address of c-ax62fdfb Value of a-10.200000 Value of b-2 Value of c-a Value of pointer p1-6487552 Value of pointer p2-6487548 Value of pointer p3-6487547 Size of a-8 size of b=4 Size of c-1 Size of pointer p1-8 Size of pointer p2-8 Size of pointer p3-8 Process exited after θ.04311 seconds with return value θ Press any key to continue . .

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Part II

##########

#include<stdio.h>
void ptrLab1(int xval){
   int x;
   x=xval;
   printf("Value of x=%d and Address of x=%p\n",x, (void*)&x);
}
void ptrLab2(int dummy){
   int y;
   printf("Value of y=%d and Address of y = %p\n",y, (void*)&y);
}
int main(){
   ptrLab1(7);
   ptrLab2(11);
   return 0;
}

//################## PGM END ################################

OUTPUT
########

C:UsersJijinA Documents\DevC++_Workspace\Program2.exe Value of x-7 and Address of x-00e00000062FDEC Value of y 7 and Address of y000000000062FDEC Process exited after e.04031 seconds with return value Press any key to continue .