Prove the statement n cents of postage can be formed using just 4-cent and 11-cent stamps using mathematical induction, where n ≥ 30.

Base Case : 30 cents can be formed using two 11-cent stamps and two 4-cent stamps as 2*11+2*4 = 30
Inductive Hypothesis : If k > 30, then we can from a k-cent stamps using only 4-cent and 11-cent stamps.
The Inductive steps of the Proof are as follows :
Step 1 : If k cents included an 11-cent stamp, then replace it by three 4-cent stamps (3+4 = 11+1), and we have formed k+1 cents in postage.
Step 2 : Otherwise, k cents was formed from just 4-cent stamps.
Step 3 : Because k > 30 there must be at least eight 4-cents stamp involved.
Step 4 : Replace eight 4-cent stamps by three 11-cents stamps, and we have formed k+1 cents in postage (3*11 = 8*4+1)
We have covered all possible cases and we can show that from if k cents could be formed from 4-cent and 11-cent stamps then k+1 cents can be formed also. This completes our inductive proof.
Note that in Step 3 we have taken k>30 this is because we have tested our base case of 30 cents already. Also, we conclude that at least eight 4-cent stamps are required because k>30 is 31 (which requires at least one 11-cent stamp and as we are considering the case of formation using only 4-cent stamps, hence it does not count) and then 32 which requires eight 4-cent stamp.
Prove the statement n cents of postage can be formed using just 4-cent and 11-cent stamps...
4. Let P(n) be the statement that a postage of n cents can be formed using just 4-cent stamps and 7-cent stamps. The parts of this exercise outline a strong induction proof that P (n) is true forn > 18. a) Show statements P(18), P(19), P (20), and P(21) are true, completing the basis step of the proof. b) What is the inductive hypothesis of the proof? c) What do you need to prove in the inductive step? d) Complete...
3. Let P(n) be the statement that a postage of n cents can be formed using just 3-cent stamps and 5-cent stamps. The 5 / Induction and Recursion parts of this exercise outline a strong induction proof that P(n) is true for n 18. a) Show statements P(18), P(19), P(20), and P(21) are true, completing the basis step of the proof. b) What is the inductive hypothesis of the proof? c) What do you need to prove in the inductive...
Use strong induction to show that any amount of postage more than one cent can be formed using just two-cent and three-cent stamps. (please be detailed!)
Please show all the steps and explain.
Prove that every amount of postage of 18 cents or more can be formed using just 4-cent and 7-cent stamps
Prove that every amount of postage of 18 cents or more can be formed using just 4-cent and 7-cent stamps
3 For each positive integer n, define E(n) 2+4++2n (a) Give a recursive definition for E(n). (b) Let P(n) be the statement E(n) nn1)." Complete the steps below to give a proof by induction that P(n) holds for every neZ+ i. Verify P(1) is true. (This is the base step.) ii. Let k be some positive integer. We assume P(k) is true. What exactly are we assuming is true? (This is the inductive hypothesis.) iii. What is the statement P(k...
Prove using mathematical induction that for every positive integer n, = 1/i(i+1) = n/n+1. 2) Suppose r is a real number other than 1. Prove using mathematical induction that for every nonnegative integer n, = 1-r^n+1/1-r. 3) Prove using mathematical induction that for every nonnegative integer n, 1 + i+i! = (n+1)!. 4) Prove using mathematical induction that for every integer n>4, n!>2^n. 5) Prove using mathematical induction that for every positive integer n, 7 + 5 + 3 +.......
please answer all the questions.
just rearranging. Explanation is not needed.
Use modular arithmetic to prove that 3|(221 – 1) for an integer n > 0. Hence, 3|(221 – 1) for n > 0. To show that 3|(221 – 1), we can show that (221 – 1) = 0 (mod 3). We have: (221 – 1) = (4” – 1) (mod 3) Then, (22n – 1) = (1 - 1) = 0 (mod 3) Since 4 = 1 (mod 3),...
QUESTION number #3
Assa3pdt Adobe Acrobat Reader D ile Edit Vie Windaw Help Home Tools Assg3.pdf × MATH1100M updat.. MATH13COM 43-4... 13536 ti Share » Write your name on each page and number each page * Clearly indicate which problem you are solving * Submit your assignments at the beginning of the class on April 02, 2019 → Export PDF Adobe Export PDF Convert PDF Files to Word or Excel Online Selact PDF File 1. (20 points) Find a formula...
NUMBER 3 AND 4 PLEASE! I JUST NEED #3 AND 4
Ozone Formation: NO2(g), is formed by chemical reactions involving N2(g) and O2(g) at the high temperatures Inside internal combustion engines in our cars. In the presence of sunlight, NO2(g) reacts with O2(g) to generate Os(s) as described by the following overall reaction: NO2(g) + O2(g) = NO(g) + O2(g) E = 306.5 l/mol This chemical process occurs in two steps, as illustrated in the potential energy diagram. In the...
Please do exercise 129:
Exercise 128: Define r:N + N by r(n) = next(next(n)). Let f:N → N be the unique function that satisfies f(0) = 2 and f(next(n)) =r(f(n)) for all n E N. 102 1. Prove that f(3) = 8. 2. Prove that 2 <f(n) for all n E N. Exercise 129: Define r and f as in Exercise 128. Assume that x + y. Define r' = {(x,y),(y,x)}. Let g:N + {x,y} be the unique function that...