Question

12. What is the velocity of a tennis ball just after release from a toss straight up (vertical) into the air given the following information: The ball weighs 0.7 N and was tossed with vertical force applied of 10 N for 1.2 sec.

Answer 1

Vertical force on ball F=10N

Weight of ball W= 0.7N

Now net force on the ball in upward direction

Fnet (10 - 0.7)N

Now impulse = change in linear momentum

$F_{net}\times time = m(v_f-v_i)$

$9.3 N\times 1.2 s= \frac{0.7}{9.8}(v-0)$

$v= \frac{9.3\times 1.2 \times 9.8}{0.7}. m/s$

Thanks for asking.