I would just like to point out (cause I know someone is gonna try this if I don't mention it), this is NOT problem 9.48 from the textbook. You will likely find a problem similar to this, but it is different. Please do NOT post the solution to problem 9.48.
Homework Answers
Line size = 128 Bytes -> Block Offset = log 128 =7 bits.
16-way set associative means, total #of block inside each set = 16
Therefore total # of set inside cache = total # of block /16
= 64*1024/16 = 4*1024 = 4K
Therefore set Index bits = log 4K = 12 bits.
Therefore tag bits = 64 - (12+7) = 64 - 19 = 45 bits.
| Tag(45 bits) | SetIndex(12 bits) | BlockOffset ( 7 bits) |
If you have any questions comment down and please? upvote thanks...
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given this problem. The problem is solved here completely from 1to6
i just wanted a quick run down on how the numbers were obtained,
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used
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