Question

Evaluate the surface integral. 1. (x2+42+7) o ds S is the part of the cylinder x2 + y2 = 4 that lies between the planes z = 0

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Answer #1

Z=0 and 7=2 ول K 1 0 Hence, the reduired value of the given surface intregnal in Given that, Lu (24030429.85 ]] (rl+gº+29.85

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